编程:扑克牌0-10的牌,每个数字4张,加上两张‘王’的牌,抽出五张牌判断5张是为顺子(‘王’做任意牌)
发布人:shili8
发布时间:2025-02-15 01:16
阅读次数:0
**扑克牌游戏**
###介绍本项目旨在模拟一副标准的扑克牌,包含数字牌(0-10)和两张"王"牌。玩家将抽取五张牌,并判断这些牌是否构成顺子。
### 牌组结构
class Card: def __init__(self, suit, value): self.suit = suit self.value = valueclass Deck: def __init__(self): self.cards = [] self.suits = ['红桃', '黑桃', '梅花', '方块'] self.values = [0,1,2,3,4,5,6,7,8,9,10, '王'] for suit in self.suits: for value in self.values: self.cards.append(Card(suit, value)) def shuffle(self): import random random.shuffle(self.cards) class PokerGame: def __init__(self): self.deck = Deck() self.deck.shuffle() def draw_cards(self, num): return [self.deck.cards.pop() for _ in range(num)]
### 牌组示例
game = PokerGame() print(game.draw_cards(5))
### 检查顺子
def is_flush(hand):
"""检查牌是否同花"""
suit = hand[0].suit for card in hand:
if card.suit != suit:
return False return Truedef is_straight(hand, wild_card=False):
"""检查牌是否顺子"""
values = sorted([card.value for card in hand])
# 如果有王,尝试将其替换为任意值 if wild_card and '王' in values:
values.remove('王')
values.insert(0,0) # 将王牌视为最小值 # 检查是否是顺子 for i in range(len(values) -1):
if values[i] +1 != values[i+1]:
return False return Truedef check_hand(hand):
"""检查手牌"""
if is_flush(hand) and is_straight(hand, wild_card=True):
print("顺子!")
else:
print("不是顺子")
### 游戏示例
game = PokerGame() hand = game.draw_cards(5) check_hand(hand)
本项目模拟了一副标准的扑克牌,并提供了检查手牌是否为顺子的功能。玩家可以通过抽取五张牌并调用`check_hand()`函数来判断这些牌是否构成顺子。

